x^2+16=12

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Solution for x^2+16=12 equation: 



x^2+16=12

We move all terms to the left:

x^2+16-(12)=0

We add all the numbers together, and all the variables

x^2+4=0

a = 1; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·1·4
Δ = -16
Delta is less than zero, so there is no solution for the equation

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